1167：再求f(x,n)

#include <bits/stdc++.h>
using namespace std;
double f(double x,int n){
    if(n==1) return x/(1+x);
    return x/(n+f(x,n-1));
}
int main()
{
    double x;
    int n;
    cin>>x>>n;
    //cout<<fixed<<setprecision(2)<<f(x,n);
    printf("%.2lf",f(x,n));//scanf
    return 0;
}